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Close focus distance for RF100mm F2.8 L MACRO IS USM

wes1790
Apprentice

What is the distance between the subject and lens front [filter ring] at 1.4x maximum magnification for 

RF100mm F2.8 L MACRO IS USM?

Does anyone have a chart showing subject size at various lens-to-subject distances?

3 REPLIES 3

rs-eos
Elite
Elite

Note that focusing distances are not typically computed from the front of the lens, but instead from the sensor.  Your camera should have a symbol of a circle with a line running through it (typically near the viewfinder).

Pages 13 and 14 of the User Manual should include all the information you're after (to include distances from the from the front of the lens).

--
Ricky

Camera: EOS 5D IV, EF 50mm f/1.2L, EF 135mm f/2L
Lighting: Profoto Lights & Modifiers

wes1790
Apprentice

I don't care how far it is from the sensor to the subject; what counts is the working distance from the front of the lens to the subject: 0.28' or 3.36" according to the user Manual. Thanks.  A chart of subject size and distance from the lens would still be helpful. 

shadowsports
Legend
Legend

Greetings,

I found the information Ricky provided to be helpful.  MFD is an industry specification.  Since MFD is calculated from the subject to the sensor, this is the information provided by the manufacturer.

The lens is approx 5.8 in.  Add a filter its approx 5.825

Mag 1.4x is 10.32 in 

Mag 1.0x is 11.04 in

Mag .5x is 15 in

Lens measurement is from the front of the lens to the flange. 

Flange distance on an RF lens is 20mm or .787 in

So if you take the lens and filter (if applicable) 5.825 + the distance from the flange to the sensor .787 = 6.612 in

Mag 1.4x is 10.32 in - 6.612 in = 3.708 in

Mag 1.0x is 11.04 in - 6.612 in = 4.428 in

Mag .5x is 15 in - 6.612 in = 8.388 in

The MFD at 1.4x is 10.32.  The lens + filter is 5.825 in = 4.495 in. - (minus) the flange distance .787 in = 3.708 in

Someone should probably verify my calculations 🤣

~Rick
Bay Area - CA


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