10-16-2017 02:55 PM - edited 10-16-2017 02:56 PM
I wanted to know the exact location of an image I created and so I got the GPS info from the metadata, it said:
Longitude 62; 7; 26.8619
Latitude 7; 4; 47.6579
For the life of me, I cannot figure out how to enter this into Google Maps to see my location.
Google says there are three ways to enter this into Maps, but the Canon data doesn't seen to match any of their formats:
Does anyone know how to translate the Canon data into something Google Maps can understand?
Each time I try entering it, it says I was in the Phillipines (I was not!).
Thanks for any help someone could offer!
Cole
10-16-2017 03:15 PM
Are you close to the equator? You have to be if the lattitude is +/- 7 degrees.
Could you have lat.long mixed up.
10-16-2017 03:24 PM
Thank you "respected" Kvbarkley!
No, I was close to the Arctic Circle.
10-16-2017 03:26 PM
I did mix up the latitude / longitude up in the post, but I think I entered it correctly in Google Maps.
I think my problem is the format for entering it.
10-16-2017 03:31 PM
Hey there, thompsoncd!
You're going to want to use the Map Utility software that came with the camera.
If you don't have it, you can download it from the Canon site HERE.
We hope this helps!
10-16-2017 04:20 PM - edited 10-16-2017 04:22 PM
Norway? It is about 62 degree N, 7 E.
I would guess the format is degrees, minutes, fractional seconds
So for your latittude 62° 7' 26.86"
10-16-2017 07:12 PM
Well, that format (thanks kvbarkley) got me MUCH closer! But it put me in Norway and I was in the Faroe Islands.
I entered: 62° 7' 26.86", 7° 4' 47.66. It got the latitude right, but the longitude wrong.
I manually located my shooting position on Google maps and then checked the lat/long and it was: 62.325086, -6.947092
That minus sign seemed significant and so I added a minus sign to my coordinates and then it worked:
62° 7' 26.86", 7° 4' 47.66
Does anyone understand the differences between Canon and Googles coordinates?
Canon 62° 7' 26.86", 7° 4' 47.66 Takes me to Norway
Google 62.325086, -6.947092 Takes me to the right place
Revised Canon: 62° 7' 26.86", -7° 4' 47.66 Takes me to the right place
I'm just curious how the nomenclature works.
Cole
10-16-2017 08:05 PM
You are looking at different units of measure of angle. Google is decimal degrees. Canon is Degrees-Minutes=Seconds.
10-17-2017 09:36 AM
It is how they specify east and west, either with an E/W or a +/- .
10-17-2017 10:20 AM - edited 10-17-2017 10:20 AM
I'm not sure what viewer you are using to look at your meta-data. When I look at the info in Canon's Digital Photo Professional 4 software (right click the info and pick 'Info' then scroll down to the GPS section) I notice that for my camera there is a trailing N/S E/W value. For example, the rows for GPS data in a sample image I selected say:
Latitude 42 18 15.6 N
Longitude 83 13 23.3 W
Altitude 180.50m
For declination values, some systems express latitudes north of the equator as positive and south of the equator as negative. For longitude values, some systems express longitudes west of the prime meridian as negative and right of the prime meridian as positive. So for example, if you were west of the prime meridian... instead of say you were so many degrees "West" you would just enter than as negative degrees.
When I look at the value in your file, I don't see the cardinal directions (N/S/E/W ... and you mention that the longitude only worked out correctly if it was expressed as a negative value, but I don't see that either.
You might try opening the image with Canon DPP4 and see how it's listed there. This may be a nuance specific to whatever software you were using to view the coordinates (how it was decoding and displaying the coordinates.) For what it's worth... I also use Adobe Lightroom and if I pick an image and view it in the "Map" module (which drops a pin on the map to mark the location where I took the photo) it is also correct (and correctly lists my longitudes which are "west" of the prime meridian.)
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